Question

P and q can complete a work in 6 and 12 days respectively.If p joins q after 6 days, in how many days whole work completed

Answer 1

Solutions :-

Given :
P and Q can complete a work in 6 and 12 days respectively.
P joins Q after 6 days.

P's one day work = 1/6

Q's one day work = 1/12
Q's six days work = 1/12 × 6 = 6/12 = 1/2

Remaining work = 1 - 1/2 = 1/2

(P + Q)'s one day work = 1/6 + 1/12
= (2 + 1)/12
= 3/12
= 1/4

1/4 work completed by (P + Q) in 1 days.
1 work completed in (4 × 1)/1 = 4 days.
1/2 work completed in 1/2 × 4 = 2 days.


Hence,
P and Q together complete the remaining work in 2 days and they can complete the total work in (6 + 2) = 8 days.

Answer 2

Answer:

8 days

Step By Step Explanation:

Given that;
P and Q can complete a work in 6 and 12 days respectively.

Now,
If P joins Q after 6 days.

1 day work of P = 1/6
1 day work of Q = 1/12
6 days work of Q = 6/12 = 1/2

Hence, Remaining work = 1 - 1/2 = 1/2

1 day work of [P + Q] = 1/6 + 1/12
⇒ (1 × 2 + 1 × 1)/12
⇒ (2 + 1)/12
⇒ 3/12
⇒ 1/4

1/4 work completed by (P + Q) in 1 day.
1 work completed in (4 × 1)/1 = 4 days.
1/2 work completed in 1/2 × 4 = 2 days.

Therfore,
Togetherly, P and Q complete the remaining work in 2 days and they can complete the whole work in (6 + 2) = 8 days.

Hence, The Required days in which whole work can be completed is 8 days.