Question

P and Q can do a piece of work in 18 days, Q and R can do it in 24 days, R and P can do it in 20 days. How much time will R alone take to finish the job? ​

Answer 1

Step-by-step explanation:

P and Q do (1/18)th of the work in 1 day.

P and R do (1/12)th of the work in 1 day.

Q and R do (1/9)th of the work in 1 day.

2P+2Q+2R do (1/18)+(1/12)+(1/9) = (6+9+12)/108 = 27/108 = (1/4)th, or

P, Q and R do (1/8)th of the work in 1 day.

So Q alone can do (1/8)-(1/12) = (3–2)/24 = 1/24th of the work in 1 day.

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Answer 2

Step-by-step explanation:

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