Math, asked by ishika8537, 1 year ago

P and Q invest rupees 36000 and Rs 25, 000 respectively at the same rate of interest per year. if at the end of 4 years p get rupees 3080 interest then you find the rate of interest

Answers

Answered by aman3495
14
p =36000 rs
q=25000 rs

Difference between p and q =
36000-25000=11000

difference between the interest = 3080

time = 4 years

rate of interest = interest * 100/ principal * time =

= 3080* 100/ 11000* 4
rate = 7% ans


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shreya32457: read the question carefully..... there isn't the difference is written
aman3495: hey shreya you can read the question carefully
Answered by shreya32457
4



⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

PERIOD = 4 YEARS....

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

SUPPOSE RATE = R

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THE DIFFERENCE BETWEEN THE INTEREST :

= 36000 - 25000

= 11000 RS

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

PRINCIPLE :

11,000 RS



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SIMPLE INTEREST =

PRINCIPLE * PERIOD * RATE / 100

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BY SUBSTITUTING THE VALUES.....

3,080 = 11,000 * 4 * R / 100

3,080 = 440 * R

R = 3080 / 440

R = 7 %

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

ishika8537: i am really really really really heartly sorry. but your answer is wrong
shreya32457: ohh ! :-(
shreya32457: what is the answer
shreya32457: sorry....☺
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