p(p+2)=0 solve quadratic equation
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Answers
Answered by
12
Hey user !!
Here is your answer !!
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Given ->P(P+2)
Solution ->P^2+2P-0=0
D=b^2-4ac
D=2-4(1)(0)
D=2-0=2
Roots exist!
-b+√D/2 , -b-√D/2
(-2+√2)/2 , (-2-√2)/2
-1+(√2)/2 , -1-(√2)/2
Hope it is satisfactory :-)
_____________________________________
Here is your answer !!
________________________________________
Given ->P(P+2)
Solution ->P^2+2P-0=0
D=b^2-4ac
D=2-4(1)(0)
D=2-0=2
Roots exist!
-b+√D/2 , -b-√D/2
(-2+√2)/2 , (-2-√2)/2
-1+(√2)/2 , -1-(√2)/2
Hope it is satisfactory :-)
_____________________________________
Answered by
2
hiii. ........friend
the answer is here,
=>p (p+2) =0.
So,
p =0.
or
p+2 =0.
p=-2.
So, The value of p is 0 or -2.
:-)Hope it helps u.
the answer is here,
=>p (p+2) =0.
So,
p =0.
or
p+2 =0.
p=-2.
So, The value of p is 0 or -2.
:-)Hope it helps u.
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