Math, asked by meghna45, 1 year ago

p(p+2)=0 solve quadratic equation


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Answers

Answered by Anonymous
12
Hey user !!

Here is your answer !!

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Given ->P(P+2)

Solution ->P^2+2P-0=0

D=b^2-4ac

D=2-4(1)(0)

D=2-0=2

Roots exist!

-b+√D/2 , -b-√D/2

(-2+√2)/2 , (-2-√2)/2

-1+(√2)/2 , -1-(√2)/2

Hope it is satisfactory :-)
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Answered by jaya1012
2
hiii. ........friend

the answer is here,

=>p (p+2) =0.

So,

p =0.

or

p+2 =0.

p=-2.

So, The value of p is 0 or -2.


:-)Hope it helps u.
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