Math, asked by chandra531400, 11 months ago

P.T √1+sinA÷1-sinA=secA+tanA

Answers

Answered by shaivyvi75

1

Answer:

LHS=√1+SinA

√1-sinA

= √1+sinA *√1+sinA

√1-sinA. √1+sinA

=√(1+sinA)^2

√1-sin^2A

=1+sinA

cosA

= secA + TanA

=RHS

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