Question

p(x)=12-x-xsquare find the value of p(-2)

Answer 1

HERE IS YOUR ANSWER...⬇⬇

$\underline{SOLUTION}$ ➡

$Given \: ,\\ \\ p(x) = 12 - x - x {}^{2} \\ \\ \\ By \: \: putting \: \: the \: \: value \: \: of \: \: x = - 2 \: \: \\ in \: \: p(x) \: \: ,\: we \: \: get \\ \\ p( - 2) = 12 - ( - 2) - ( - 2) {}^{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = 12 + 2 - 4 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = 14 - 4 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = 10$

$\underline{ANSWER}$ ➡

$Value \: \: of \: \: p( - 2) = 10$

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Answer 2

p(-2)=12-(-2)-(-2)square
p(-2)=12+2-4
p(-2)=14-4
p(-2)=10

the value of p(-2) is 10

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