p(x)=4x²+9x+5,Find the zeros of the given quadratic polynomial.
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Answered by
24
given p(x)=4x^2+9x+5
4x^2+4x+5x+5
4x(x+1)+5(x+1)
4x+5=0 or x+1=0
x=-5/4 orx=-1
these are the zero of the polynomial
4x^2+4x+5x+5
4x(x+1)+5(x+1)
4x+5=0 or x+1=0
x=-5/4 orx=-1
these are the zero of the polynomial
Answered by
11
Solution :
Given p(x) = 4x² + 9x + 5
Let p(x) = 0
=> 4x² + 9x + 5 = 0
Splitting the middle term, we get
=> 4x² + 4x + 5x + 5 = 0
=> 4x( x + 1 ) + 5( x + 1 ) = 0
=> ( x + 1 )( 4x + 5 ) = 0
x + 1 = 0 or 4x + 5 = 0
x = -1 or x = -5/4
Therefore ,
-1 , -5/4 are two zeroes of given
quadratic polynomial p(x).
••••
Given p(x) = 4x² + 9x + 5
Let p(x) = 0
=> 4x² + 9x + 5 = 0
Splitting the middle term, we get
=> 4x² + 4x + 5x + 5 = 0
=> 4x( x + 1 ) + 5( x + 1 ) = 0
=> ( x + 1 )( 4x + 5 ) = 0
x + 1 = 0 or 4x + 5 = 0
x = -1 or x = -5/4
Therefore ,
-1 , -5/4 are two zeroes of given
quadratic polynomial p(x).
••••
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