p(x)=3x²+5x–8,Find the zeros of the given quadratic polynomial.
Answers
Answered by
1
two solution are enough to find.
hope it will helps you......
hope it will helps you......
Attachments:
Answered by
15
Solution :
Given p(x) = 3x² + 5x - 8
Let p(x) = 0
=> 3x² + 5x - 8 = 0
Splitting the middle term , we get
=> 3x² - 3x + 8x - 8 = 0
=> 3x( x - 1 ) + 8( x - 1 ) = 0
=> ( x - 1 )( 3x + 8 ) = 0
x - 1 = 0 or 3x + 8 = 0
x = 1 or x = -8/3
Therefore ,
1 , (-8/3 ) are two zeroes of given
quadratic polynomial p(x).
•••••
Given p(x) = 3x² + 5x - 8
Let p(x) = 0
=> 3x² + 5x - 8 = 0
Splitting the middle term , we get
=> 3x² - 3x + 8x - 8 = 0
=> 3x( x - 1 ) + 8( x - 1 ) = 0
=> ( x - 1 )( 3x + 8 ) = 0
x - 1 = 0 or 3x + 8 = 0
x = 1 or x = -8/3
Therefore ,
1 , (-8/3 ) are two zeroes of given
quadratic polynomial p(x).
•••••
Similar questions