p(x)=x²–81 ,Find the zeros of the given quadratic polynomial.
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two solution are enough to find.
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Solution :
Given p(x) = x² - 81
Let p(x) = 0
=> x² - 81 = 0
=> x² - 9² = 0
=> ( x + 9 )( x - 9 ) = 0
x + 9 = 0 or x - 9 = 0
x = -9 or x = 9
Therefore ,
-9 , 9 are two zeroes of given
quadratic polynomial p(x).
••••
Given p(x) = x² - 81
Let p(x) = 0
=> x² - 81 = 0
=> x² - 9² = 0
=> ( x + 9 )( x - 9 ) = 0
x + 9 = 0 or x - 9 = 0
x = -9 or x = 9
Therefore ,
-9 , 9 are two zeroes of given
quadratic polynomial p(x).
••••
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