Math, asked by nirajkumar2705, 11 months ago

p(x)=
 {x}^{3}  - 3 {x}^{2}  + 2x - 6

Answers

Answered by atharvrastogi566
0

Answer:

 {x}^{3}  - 3 {x}^{2}  + 2x - 6 \\  {x}^{2}(x - 3) + 2(x - 3) \\ (x - 3)( {x }^{2}  + 2)

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Answered by itzBrainlyBoy
59

\huge{\boxed{\mathfrak\blue{\fcolorbox{white}{white}{..!!Hello Dear!!...}}}}{\bold{\huge{\red{\underline{\red{A}\red{ns}\red{wer}\red{!!!!!...}}}}}}

x {}^{2}  - 3x {}^{2}  + 2x - 6  \\ x {}^{2} (1 - 3) + 2(1 - 3 ) \\( x {}^{2}  + 2)(1 - 3)

\huge{\boxed{\mathcal\green{\fcolorbox{white}{white}{..!!Brainliest!!...}}}}✔️✅

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