Question

P (x) = x^2 + 13x + 12
find x​

Answer 1

$p(x) = {x}^{2} + 13x + 12 \\ \\ = {x}^{2} + x + 12x + 12 \\ \\ = x(x + 1) + 12(x + 1) \\ \\ = (x + 12)(x + 1) \\ \\ (x + 12) = 0 \: or \: (x + 1) = 0 \\ \\ x = - 12 \: or \: x = - 1$