Question

p(x)=x^3-x^2-x-5 find p(-1)​

Answer 1

Answer:

-6

Step-by-step explanation:

Given

$p(x) = {x}^{3} - {x}^{2} - x - 5$

$p( - 1) = {( - 1)}^{3} - {( - 1)}^{2} - ( - 1) - 5$

$p( - 1) = - 6$

Hope it helps