Question

two ships are anchored on opposite sides of a lighthouse. their angles of depression as observed from the top of the lighthouse are found to be 30 degree and 45 degree the line joining the ships passes through the foot of the lighthouse ...if the height of the lighthouse is 100m , find the distance between the ships..

Answer 1

Answer:

Step-by-step explanation:

From right angled △ABC,

tan 30˚ = AC/BC

⇒ 1/√3 = 90m/BC

⇒ BC = [90 × √3] m

∴ BC = 155.88 m

Again from right angled △ACD,

tan 45˚ = AC/CD

⇒ 1 = 90 m/CD

⇒ CD = 90 m

Hence, the distance between the two ships = BC + CD = (155.88 + 90) m

= 245.88 m

Hope it helps

:)

Answer 2

Answer:

From a light house, the angles of depression of two ships on opposite sides of the light house were observed to be 30˚ and 45˚. If the height of the light house is 90 metres and the line joining the two ships passes through the foot of the light house, find the distance between the two ships, correct to two decimal places.