p(x)=x³–x²–x+1,Factorize the given polynomial.
Answers
Answered by
6
p(x) =( x+ 1) ( x - 1) ( x- 1)
Attachments:
Answered by
2
Solution :
Given Cubic polynomial
p(x) = x³ - x² - x + 1
= x²( x - 1 ) - 1( x - 1 )
= ( x - 1 )( x² - 1 )
= ( x - 1 )( x² - 1² )
= ( x -1 )( x + 1 )( x - 1 )
[ By algebraic identity,
a² - b² = ( a + b )( a - b ) ]
Therefore ,
p(x) = ( x -1 )( x -1 )( x + 1 )
••••
Given Cubic polynomial
p(x) = x³ - x² - x + 1
= x²( x - 1 ) - 1( x - 1 )
= ( x - 1 )( x² - 1 )
= ( x - 1 )( x² - 1² )
= ( x -1 )( x + 1 )( x - 1 )
[ By algebraic identity,
a² - b² = ( a + b )( a - b ) ]
Therefore ,
p(x) = ( x -1 )( x -1 )( x + 1 )
••••
Similar questions