Question

(x–3) is a factor of p(x)=x²–2x–3,Examine the validity of the given statement.

Answer 1

Putting x=3
9-6-3=0
therefore.. that statement is true..

Answer 2

Solution :

It is True .

Explanation :

Given p(x) = x² - 2x - 3

By factor theorem ,

if ( x - 3 ) is a factor of p(x) then

p(3) = 0

Now ,

p(3) = 3² - 2×3 - 3

= 9 - 6 - 3

= 9 - 9

= 0

Therefore ,

p(3 ) = 0 ,

( x - 3 ) is a factor of p(x)

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