(x–1) is a factor of p(x)=x⁴–2x³+3x–2,Examine the validity of the given statement.
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(x - 1) is a factor of P(x) = x⁴ - 2x³ + 3x - 2
means, x = 1 is a root of P(x) = x⁴ - 2x³ + 3x - 2.
P(1) = 1⁴ - 2(1)³ + 3(1) - 2
P(1) = 1 - 2 + 3 - 2
P(1) = 4 - 4 = 0
we get, P(1) = 0 hence, the given statement is correct that (x - 1) is a factor of p(x)=x⁴–2x³+3x–2.
means, x = 1 is a root of P(x) = x⁴ - 2x³ + 3x - 2.
P(1) = 1⁴ - 2(1)³ + 3(1) - 2
P(1) = 1 - 2 + 3 - 2
P(1) = 4 - 4 = 0
we get, P(1) = 0 hence, the given statement is correct that (x - 1) is a factor of p(x)=x⁴–2x³+3x–2.
Answered by
0
Hi ,
p( x ) = x⁴ - 2x³ + 3x - 2 ,
and g( x ) = x - 1 ,
The zero of g( x ) is 1 ,
Then p( 1 ) = 1⁴ - 2 × 1³ + 3 × 1 - 2
= 1 - 2 + 3 - 2
= 4 - 4
= 0
So , by Factor Theorem , ( x - 1 ) is a factor
of p( x ).
I hope this helps you
: )
p( x ) = x⁴ - 2x³ + 3x - 2 ,
and g( x ) = x - 1 ,
The zero of g( x ) is 1 ,
Then p( 1 ) = 1⁴ - 2 × 1³ + 3 × 1 - 2
= 1 - 2 + 3 - 2
= 4 - 4
= 0
So , by Factor Theorem , ( x - 1 ) is a factor
of p( x ).
I hope this helps you
: )
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