Question

p(y) =3y cube-4y+root11 at y=2​

Answer 1

Answer:

16+√11

Step-by-step explanation:

p(y) = 3y³ - 4y + √11

at y=2

3(2)³ - 4(2) + √11

3(8) - 8 + √11

24 - 8 + √11

16+√11

Answer 2

Answer:

Answer:

x = 0 \\ y = 0 \\  

Solution:

\sqrt{2x}  -  \sqrt{3y}  = 0 \\  \\ \sqrt{2x}  =  \sqrt{3y} \\  \\ squaring \: both \: side \\  \\ 2x = 3y \\  \\ 2x - 3y = 0 \:  \:  \: eq1 \\  \\  \sqrt{5x}  +  \sqrt{2y}  = 0  \\ \\ squaring \: both \: side \\  \\  \sqrt{5x}  =  -  \sqrt{2y}  \\  \\ 5x = 2y \\  \\ 5x - 2y = 0 \:  \:  \: eq2 \\  \\  

From eq 1 and eq2

multiply eq 1 by 5 and eq2 by 2 and subtract both

10x - 9y = 0 \\ 10x - 4y = 0 \\  -  \:  \:  \:  +  \:  \:  \:  \:  \\  - 5y = 0 \\  \\ y =  \frac{ - 0}{5}  \\  \\ y = 0 \\  \\  

put value of y in eq 1

2x - 3(0) = 0 \\  \\ 2x = 0 \\  \\ x =  \frac{0}{2}  \\  \\ x = 0 \\  

So, x= 0

y= 0

Step-by-step explanation: