write reaction of aluminum with HCL and NaOH
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2 Al + 2 NaOH + 2 H2O → 2 NaAlO2 + 3 H.
2Al(s) + 6HCl(aq) = 2AlCl3(aq) + 3H2(g).
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2Al + 6HCl = 2AlCl3 +3H2
2Al + 2NaOH + 2H2O = 2NaAlO2 + 3H2
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