Question

p3+q3 when p+q=10 and pq=9

Answer 1

here is your answer ........

Answer 2

${p}^{3} + {q}^{3} = {(p + q)}^{3} - 3pq(p + q)$
Now we have,
p+ q = 10
and pq = 9

Substitute for them in above equation and you'll get:

${10}^{3} - 3(9)(10) \\ = 1000 - 270 \\ = 730$


So, the solution of your question is 730.