Question

प्र.4 सही जोडी बनाइये
2Sin (CP) Cos (SP)
1. ncr
2. (a+b)
3. SinC+SinD
4. sin 750
2
А
3+1
2
n!
(n-r)!r!
(n-r)!»r!
√2+12
5. (A)​

Answer 1

Answer:

The maximum area of the triangle formed

by the points (0,0), (acos tita , bsin tita ) and

(acos tita , -b sin tita) (in square units)

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