Math, asked by PragyaTbia, 1 year ago

प्रश्न 1 से 22 तक निम्नलिखित सीमाओं के मान प्राप्त कीजिए : \lim_{x\rightarrow \pi}\dfrac{\sin (\pi - x)}{\pi (\pi - x)}

Answers

Answered by kaushalinspire
0

Answer:

Step-by-step explanation:

\lim_{x\rightarrow \pi}\dfrac{\sin (\pi - x)}{\pi (\pi - x)}

माना कि  π - x  =  y   जबकि    

x → π

y → 0

\lim_{y\rightarrow 0} \frac{\sin y}{y} .\frac{1}{\pi} \\\\=\frac{1}{\pi} [\lim_{y\rightarrow 0} \frac{\sin y}{y}]\\\\=\frac{1}{\pi} .1\\\\=\frac{1}{\pi}

अतः  \lim_{x\rightarrow \pi}\dfrac{\sin (\pi - x)}{\pi (\pi - x)}  का मान   \frac{1}{\pi}होगा।

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