Math, asked by vipulvarsha1321, 11 months ago

प्रश्न 1 से 6 तक की असमिकाओं को हल कीजिए: -15 \  \textless \  \dfrac{3(x - 2)}{5} \leq 0

Answers

Answered by amitnrw
0

- 23 < x  ≤  2 , x ∈ ( -23 , 2 ]  यदि -15  <  3(x - 2) /5 ≤ 0

Step-by-step explanation:

-15  <  3(x - 2) /5 ≤ 0

=> 5 * (-15) <  5 * 3(x - 2) /5 ≤   5 *0

=> -75  <  3(x - 2) ≤  0

=> -75/3  <  3(x - 2)/3  ≤  0/3

=> -25  < x - 2 ≤  0

=> -25 + 2 < x - 2 +2 ≤  0 + 2

=> - 23 < x  ≤  2

=> x ∈ ( -23 , 2 ]

और  पढ़ें

हल कीजिए : 24x < 100, जब

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"हल कीजिए: 5x – 3 < 7, जब

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