Math, asked by PragyaTbia, 11 months ago

प्रश्न 6 से 9 मे दिए गए प्रत्येक समीकरण को हल कीजिए : 27x^2 - 10x + 1 = 0

Answers

Answered by kaushalinspire
0

Answer:

Step-by-step explanation:

प्रश्नानुसार  

27x^2 - 10x + 1 = 0

यहाँ   a  = 27

        b  = -10

        c   =  1

x=\frac{-b±\sqrt{b^{2}-4ac} }{2a} \\\\=\frac{-(-10)±\sqrt{(-10)^{2}-4*27*1} }{2*27} \\\\=\frac{10±\sqrt{100-108} }{54} \\\\=\frac{10±\sqrt{-8} }{54} \\\\=\frac{10±\sqrt{-8} }{54}\\\\=\frac{10±{2\sqrt{2} }i }{54}\\\\x=\frac{5}{27}  ±\frac{\sqrt{2} }{27} i

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