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Question 1
(i) Construct a ∆DEF such that DE = 5 cm, DF = 3 cm and ∠EDF = 90°.
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Step-by-step explanation:
Step1 -draw a line DF of 3cm
Step2 -with center D construct an angel of 90 degree & name the line DX
Step3 -cut the line DX at 5cm away from D &name it E
Step4 -join FE
DEF is constructed
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