Palladium-107 undergoes b decay (t1/2 = 6.5 ´ 105 yr) to form silver-107. How long will it take for 0.150 mol of silver-107 to form from 1.25 mol of palladium-107?
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1.2×10^5 years
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It takes 1.2 * 10^5 years for 0.150 mol of silver-107 to form from 1.25 mol of palladium-107.
• T1/2 = 0.693 / K
K = 0.693 / 6.5 * 10^5 …..(i)
• Nt = 1.25 – 0.150
= 1.1 mole
• Nt = N0 e^-kt
1.1 = (1.25) e^-kt
0.88 = e^ -kt
ln 0.88 = -kt
0.128 = kt
Putting value of k from (i) ,
0.128 = (0.693 / 6.5 * 10^5 ) * t
t = 1.2 * 10^5 years
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