Math, asked by jhss9248, 1 year ago

Pandian and thamarai contested for the election to the panchayat committee from their village. Pandian secured 11,484 votes which was 44% of the total votes. Thamarai secured 36% of the votes. Calculate (i) the number of votes cast in the village and (ii) the number of voters who did not vote for both the continents

Answers

Answered by acesolution2017
12

Answer:


Step-by-step explanation:

Suppose there are x numbers of votes;

Pandian get = 11484 votes

which is 44% of the total votes = (44/100) =  0.44x = 11484;

x = 11484/0.44

x = 26100 total votes in the village

Thamarai get 36%  of the votes = (36/100)x = 0.36x

= 0.36 * 26100

= 9396

Thamarai get 9396 votes

Now calculating the number of votes who did not vote for both the continents

26100 - 9396-11484 = 5220



Answered by lodhiyal16
5

Answer:


Step-by-step explanation:

Pandian secured 11,484 votes in the election which was 44 %

that means 11,484 is 44%, By unitary method we can find out total number of votes

44% = 11,484

100 % = 11,484 /44 × 100

So the total number of votes are 26,100

Thamarai secured votes 36 % of total votes

26,100 × 36 /100

= 9,396

(1) The number of votes cast  in village = Number of votes of Pandian + Number of votes  of Thamarai

= 11,484 + 9396

= 20,880

(2). Number of voters who didnot vote = Total number of votes - Number of votes cast in village

= 26100 - 20,880

= 5220.


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