Question

Particle of mass 4 kg moves simple harmonic analysis the potential energy velocity position x as shown

Answer 1

Answer:

4kg is the answer so write it properly

Answer 2

Thus the time period of the oscillation of the particle is T = 4π / 5 s

Explanation:

Statement:

A particle of mass 2 kg moves in simple harmonic motion and its potential energy U varies with position x as shown. The period of oscillation of the particle is?

Solution:

1/2 KA^2 = 1.0

1/2 K (0.4)^2 = 1.0

Or

K = 12.5 or 25 / 2 N/m

T = 2 π √ m / k = 2π √ 2 / 25 / 2

T = 4π / 5 s

Thus the time period of the oscillation of the particle is T = 4π / 5 s