Question

Percentage of nitrogen and phosphorus in (NH4)3PO4

Answer 1

Answer:

(NH4)3PO4

= 14×3 + 4×3 + 31 + 16×4

=42 + 12 + 31 + 64

=149

% of N = 42 /149 × 100

= 28.1%

% of P = 31/149 ×100

= 20.8%

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