Perimetes of two similar traingle
ABC and pol are respectively
48 cm and 36cm if pq=12cm then an is
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Step-by-step explanation:
Form given statement: ΔABC∼ΔPQR,
PQ=12cm
Perimeter of ΔABC=AB+BC+CA=32cm
Perimeter of ΔPQR=PQ+QR+RP=24cm
Now,
PQ
AB
=
QR
BC
=
RP
CA
=
PQ+QR+RP
AB+BC+CA
=
24
32
12
AB
=
24
32
AB=
24
32×12
=16cm
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