ph of 0.00000008 Hcl
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6.98 is the answer
that is ph of HCL
that is ph of HCL
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ph = - log [ H+ ]
given,
[ H+ ] = 8 x 10^-8 M
ph = - log [H+]
= - log (8 x 10^-8)
= - { log (2)^3 + log (10^-8)}
= 8 - 3 log2
= 8 -3 x (0.301) = 8 - 0.9 = 7.1
but this is ph of Base.
if we use some concept then ph come slightly less then 7
e.g ph = 6.98
given,
[ H+ ] = 8 x 10^-8 M
ph = - log [H+]
= - log (8 x 10^-8)
= - { log (2)^3 + log (10^-8)}
= 8 - 3 log2
= 8 -3 x (0.301) = 8 - 0.9 = 7.1
but this is ph of Base.
if we use some concept then ph come slightly less then 7
e.g ph = 6.98
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