pH of given HCl solution is 4.If 1 mL of this solution is diluted to 100 mL, the pH of the resulting is
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pH = 4
hence molarity = 10^-4
for HCl molarity = normality
N1V1 = N2V2
N1 = 10^-4
V1 = 1
N2 =?
V2 = 100
N2 = 10^-6
M2 = 10^-6 = C = [H+]
pH = -log[H+]
pH = 6
hence molarity = 10^-4
for HCl molarity = normality
N1V1 = N2V2
N1 = 10^-4
V1 = 1
N2 =?
V2 = 100
N2 = 10^-6
M2 = 10^-6 = C = [H+]
pH = -log[H+]
pH = 6
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