Question

Ph value of decinormal solution of nh4oh which is 20% ionised is

Answer 1

Ph value of decinormal solution of NH4OH which is 20% ionised will be 12.3 that can be calculated as:

Decinormal solution refers to concentration is 0.1 N.

[OH−] = Cα = 0.1x0.2 = 0.02[OH−] = Cα = 0.1x0.2 = 0.02

pOH = −log[OH−] = 1.7pOH = −log⁡[OH−] = 1.7

pH = 14−pOH = 12.3