Ph value of decinormal solution of nh4oh which is 20% ionised is
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Ph value of decinormal solution of NH4OH which is 20% ionised will be 12.3 that can be calculated as:
Decinormal solution refers to concentration is 0.1 N.
[OH−] = Cα = 0.1x0.2 = 0.02[OH−] = Cα = 0.1x0.2 = 0.02
pOH = −log[OH−] = 1.7pOH = −log[OH−] = 1.7
pH = 14−pOH = 12.3
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