Question

✪ Physics ✪
100g of ice (latent heat 80g⁻¹, at 0°C) is mixed with 100g of water (specific heat 1 cal g⁻¹ °C⁻¹) at 80°C. The final temperature of the mixture will be :
(a) 0°C
(b) 40°C
(c) 80°C
(d) < 0°C
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• Proper steps required ✔︎
• Quality answer required.

Answer 1

Question :-

100g of ice (latent heat 80g⁻¹, at 0°C) is mixed with 100g of water (specific heat 1 cal g⁻¹ °C⁻¹) at 80°C. The final temperature of the mixture will be :

(a) 0°C

(b) 40°C

(c) 80°C

(d) < 0°C

____________________

Answer :-

Option (a) 0°C

Explanation and working is attached in the image above.

____________________

Answer 2

A ] 0°C

Proper Steps :

100 × 80 + 100 × 1 ( 0 - 0 ) ═══ 100 × 1 ( 80 - θ )

800 + 100θ ═══ 8000 + 100θ

200θ --- 0

θ = -- 0°

Hence , Answer is Option A

.0° C

This is the required answer .

More information

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HEAT : Heat is a form of energy which flows from a hot body to a cold body. It is measured in Calorie or Joules.

LATENT HEAT : The heat which changes the state of a substance, without any change of temperature, is called latent heat.

PRINCIPLE OF CALORIMETRY : Heat lost by the hot bodies is equal to the heat gained by the cold bodies. This is the principle of calorimetry.