Question

* Pind the attitude of a tatiangle whose area is 45 cm
and base & 450mm.
AS A D ​

Answer 1

Explanation:

{ ɴᴏᴛᴇ : ɪ ʜᴀᴅ ᴄᴏʀʀᴇᴄᴛᴇᴅ ᴛʜᴇ ᴍᴇᴀsᴜʀᴇ ᴏғ ᴛʜᴇ ʙᴀsᴇ,ᴏᴛʜᴇʀᴡɪsᴇ ᴛʜᴇ ʙᴀsᴇ ᴀɴᴅ ᴀʀᴇᴀ ᴡɪʟʟ ʙᴇ ᴏғ sᴀᴍᴇ ʟᴇɴɢᴛʜ ᴡʜɪᴄʜ ɪs ɴᴏᴛ ᴘᴏssɪʙʟᴇ ᴀɴᴅ ᴡɪʟʟ ʙᴇ ᴡʀᴏɴɢ}

Question:-

Find the altitude of a triangle whose area is 45cm and base is 45mm.

Answer:-

Given :-

• The given figure is a triangle.

• The base of the triangle is 45mm.

• The area of the triangle is 45cm.

To find :-

The altitude of the triangle

Process :-

Firstly,we have to convert all the units of the measurements into one in order to calculate:-

Base = 45mm

∴ Change of mm into cm (as area is in cm):-

$⇒ Cm = \frac{mm}{10} \\ \\ ⇒Cm = \frac{45}{10} \\ \\ ⇒Cm = 4.5cm$

Now,as we all know:-

$⇒ Area \: of \: triangle \: = \frac{1}{2} ×Base × Height$

Therefore,putting the above equation in the formula:-

{ Note that Height and Altitude has same meaning}

$⇒ Area = \frac{1}{2} × Base × Height \\ \\ ⇒45= \frac{1}{2} × 4.5 × Height \\ \\ ⇒45 × 2 = 4.5 × Height \\ \\ ⇒90 = 4.5 × Height \\ \\ ⇒ 4.5 × Height = 90 \\ \\ ⇒Height = \frac{90}{4.5} \\ \\ ⇒ Height = 20cm$

∴ We can conclude that the altitude of the triangle is 20cm.

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★ More to know

Some more formulas:-

$• \: Area \: of \: scalene \: triangle = \frac{1}{2} \times Base \times Height \\ \\ • \: Perimeter \: of \: Scalene \: triangle = a +b+c \\ \\ • \: Area \: of \: equilateral \: triangle = \frac{ \sqrt{3} }{4} {a}^{2} \\ \\ • \: Perimeter \: of \: equilateral \: triangle = 3×a \\ \\ • \: Area \: of isosceles \: triangle = \frac{b {h}^{b} }{2} \\ \\ • \: Perimeter \: of \: isosceles \: triangle= 2a + b \\ \\ • \: Area \: of \: right \: angled \: triangle = \frac{1}{2} (Base × Perpendicular) \\ \\ • \: Perimeter \: of \: right \: angled \: triangle= a + b + \sqrt{ {a}^{2} + {b}^{2} }$

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Hope it helps you...

#Be brainly