Question

Pipe A can fill a tank in 3 hours. Pipe B can fill itin 4 hours. An outlet pipe C can empty the fulltank in 6 hours. If all three pipes are kept opensimultaneously, in how many hours will the tankbe half full?​

Answer 1

Question:

Pipe A can fill a tank in 3 hours. Pipe B can fill it in 4 hours. An outlet pipe C can empty the full tank in 6 hours. If all three pipes are kept open simultaneously, in how many hours will the tank be half full?

Answer:

they'll take 0.42 hours

Step-by-step explanation:

Pipe A can fill tank in 3 hours

=> Pipe A one hour work = 1/3

Pipe B can fill in 4 hours

=> Pipe B one hour work = 1/4

Pipe C one hour work [ emptying ] = 1/6

Now, it is given that these three pipes are kept open simultaneously,

Therefore,

Time these pipes will take = 1/3 + 1/4 - 1/6

=> Time these pipes will take = 5/12

=> For half full = 12/5 => 2(2/5)

=> Time these pipes will take = 2 hours 24 minutes

So, they'll take 2 hours and 24 minutes.

Answer 2

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