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plz mark it brainlist anwer
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Opposite angles in a cyclic quadrilateral is 180, So,
4y-4x+20=180
4y-4x=160 (equation 1)
3y-5-7x+5=180
3y-7x=180 (equation 2)
multiply equation 1 by 3 and equation 2 by 4 ,
12y-12x=480 (equation 3)
12y-28y=720 (equation 4)
subtract equation 3 and 4,
-12x+28x=480-720
x=(-15)
substitute x in equation 1,
4y-4(-15)=160
4y==160-60
y=25
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