Places A and B are 30 km apart and they are on a straight road. Hamid travels from A to B on bike at the same time. Joseph starts from B on bike travel towards Each Other after 20 minutes. If Joseph would have started from be at the same time but in the opposite direction (instead of towards A ). Hamid would have caught him after 3 hours. Find the speed of Hamid and Joseph
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hey friend!!!!
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Let speed of hamid be x and joseph be y
since time=distance/speed
30/x-30/y=20/60
30/x-30/y=1/3
30(1/x-1/y)=1/3
1/x-1/y=1/3*30
1/x-1/y=1/90-------eq1
1/x+1/y=1/3+3
1/x+1/y=10/3------eq2
let 1/x=a and 1/y=b then
a-b=1/90
a+b=10/3
---------------------on solving we get
2a=301/90
a=301/180
substuding a value we get
b=299/180
Then speed of hamid=a=1/x
="180/301"
speed of joseph=b=1/y
="180/299"
hope it will help you..
_________
Let speed of hamid be x and joseph be y
since time=distance/speed
30/x-30/y=20/60
30/x-30/y=1/3
30(1/x-1/y)=1/3
1/x-1/y=1/3*30
1/x-1/y=1/90-------eq1
1/x+1/y=1/3+3
1/x+1/y=10/3------eq2
let 1/x=a and 1/y=b then
a-b=1/90
a+b=10/3
---------------------on solving we get
2a=301/90
a=301/180
substuding a value we get
b=299/180
Then speed of hamid=a=1/x
="180/301"
speed of joseph=b=1/y
="180/299"
hope it will help you..
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