Question

pleaegive me fast answer
$x { }^2 - 2x - 8$
by middle trem method

Answer 1

Hi...☺

Here is your answer...✌
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${x}^{2} - 2x - 8 \\ \\ = {x}^{2} - 4x + 2x - 8 \\ \\ = {x}(x - 4) + 2(x - 4) \\ \\ = (x +2 )(x - 4)$

Answer 2

Hii friend,

X²-2X-8

X²-4X+2X-8

X(X-4) + 2 ( X-4)

(X-4) ( X+2)

(X-4) = 0 OR. (X+2) = 0

X = 4 OR. X = -2

Hence,

4 and -2 are the two zeros of the given polynomial.


HOPE IT WILL HELP YOU... :-)