Question

please ans it ....... question 1.

Answer 1

Let the four consecutive integers be x,x+1,x+2,x+3.

Given that product of four consecutive integers = 840.

x * (x + 1) * (x + 2) * (x + 3) = 840

x^4 + 6x^3 + 11x^2 + 6x = 840

(x - 4)(x + 7)(x^2 + 3x + 30) = 0

x = 4 (or) x = -7.


Since x cannot be -ve, so x = 4.


Now,

1st number = 4

2nd number = 5

3rd number = 6

4th number = 7.


Therefore the numbers are 4,5,6,7.


Verification:

x * (x + 1) * (x + 2) * (x + 3) = 840

4 * 5 * 6 * 7 = 840

840 = 840


Hope this helps!

Answer 2

Hi,

Please see the attached file!

Thanks