Please answer.....................!!!!
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Anonymous:
42N?
Whih q?
19
Yeh ryt...go braibly answer it
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m1 and m2 are the masses of 2 blocks and ¥1 n ¥2 are the coefficient of friction.
Force is working on the lower block .... method 2 to solve this question
N =( m1+m2)g
= 14 * 10
= 140newton
1. a = F/14.......( first equation)
2. let normal on the 1st block with mass 4kg be N1
and mg on the same block will be 40newton
3. friction will act in the direction of "F" force...and coefficient of friction is 0.3 so force = 0.3 * N1
N1 = 40newton
so force = 0.3*40
= 12newton
4. finally,
a = 12/4
= 3m/s²
from 1st equation,
3 = F/14
F = 42newton
Force is working on the lower block .... method 2 to solve this question
N =( m1+m2)g
= 14 * 10
= 140newton
1. a = F/14.......( first equation)
2. let normal on the 1st block with mass 4kg be N1
and mg on the same block will be 40newton
3. friction will act in the direction of "F" force...and coefficient of friction is 0.3 so force = 0.3 * N1
N1 = 40newton
so force = 0.3*40
= 12newton
4. finally,
a = 12/4
= 3m/s²
from 1st equation,
3 = F/14
F = 42newton
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No.nee
Got it thnx
our teachers have same method to solve question
thanks
correct. we can do that in 3 to 4 lines to save time and effort...use equations to explain themselves.
ok sir... I promise you I will keep this in mind from next time
thank you sir for checking my answer
F = (m1 + m2) a = 14 a, as they move together.... Friction between the blocks supplies the force forward for m2 = 4 kg block. Max friction = Mu m2 g = m2 a.. So max a = 10 Mu = 3 .. So max F = 42 N
wow!!!! I have never thought it can be solved using less steps as well and that too is very easy to understand..... thn you sir for letting me know ur way to solve questions so nicely
thnk*
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