Question

Please answer.....50 points

Answer 1

⭕️when the lift was moving upwards acceleration was g÷4

⭕️weight will be =m×g'

⭕️Therefore m will be 400.

⭕️substitute in net acceleration which will be

⇒ g+g/4.

⭕️The weight of body due to normal reaction will be
⇒ N=mg'

Then

⇒m will be 40.

⭕️substitute in the last equation:-

⇒∴ N=M×5×g/4

∴ At the end u will get answer as 500N.

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Answer 2

Answer:

500 N

Step-by-step explanation:

hey the reading is the force on it

force on it is 300kg

when a and g acts on a body

force=mass(g-a)if acc is against gravity

300=m(10-10/4)

300=m(30/4)

1200/30=m

m=40kg

when a and g are in same direction f=m(g+a)

=40(10+10/4)

=500