Question

Please answer ASAP!​

Answer 1

Answer:

4] 100°

Step-by-step explanation:

∠DAB+∠DCB = 180°                 (given)

∴∠DCB = 180-∠DAB

∠DCB = 180-(∠DAE+30)            (∠DAB =∠DAE+30)

∠DCB = 180-30-∠DAE

∠DCB = 150-∠DAE

∠DCB+10 = 150-∠DAE+10         (adding 10 to both sides)

∠DCE = 160-∠DAE                     (∠DCE =∠DCB+10)

∠DCE = 160-∠DCE                    (Opposite angles of parallelogram are same)

2∠DCE = 160

 ∠DCE = 80

Now,

∠DCE+∠AEC = 180°    (Adjacent angles of parallelogram are supplementary)

∠AEC = 180-80

∠AEC =100