please ANSWER fast .....................
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swathi37:
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x=(b-c)(a-d)=ab-ac-bd+cd
y=(c-a)(b-d)=bc-ab-cd+ad
z=(a-b)(c-d)=ac-bc-ad+bd
Now we have to find
x3+y3+z3=???
As we know that
x3+y3+z3-3xyz =(x+y+z)(x2 +y2+ z2-xy- yz- zx)
and if x+y+z=0
then x3+y3+z3=3xyz
Now here x+y+z=0
so x3 +y3 +z3=3xyz
in this way you can find out your answer
y=(c-a)(b-d)=bc-ab-cd+ad
z=(a-b)(c-d)=ac-bc-ad+bd
Now we have to find
x3+y3+z3=???
As we know that
x3+y3+z3-3xyz =(x+y+z)(x2 +y2+ z2-xy- yz- zx)
and if x+y+z=0
then x3+y3+z3=3xyz
Now here x+y+z=0
so x3 +y3 +z3=3xyz
in this way you can find out your answer
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