Question

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Q)What volume of carbon dioxide measured at 300k and 720 mm pressure be obtained on treatement of 1 g CaCO3 with dilute HCL?
[Ca=40, C=12, O=16]​

Answer 1

Answer:

CaCO

3

+2HCl→CaCl

2

+H

2

O+CO

2

100 g 44 g

1 mole 1 mole

22.4 L 22.4 L

We know that 1 mole of any gas at 0

o

C and 1 atm pressure occupies 22.4 L volume.

So, 100 g CaCO

3

forms 22.4 L of CO

2

Hence, 2.5 g CaCO

3

will form =

100

2.5×22.4

=

100

56

L of CO

2

=0.56 L of CO

2

Answer 2

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