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Q)What volume of carbon dioxide measured at 300k and 720 mm pressure be obtained on treatement of 1 g CaCO3 with dilute HCL?
[Ca=40, C=12, O=16]
Answers
Answered by
1
Answer:
CaCO
3
+2HCl→CaCl
2
+H
2
O+CO
2
100 g 44 g
1 mole 1 mole
22.4 L 22.4 L
We know that 1 mole of any gas at 0
o
C and 1 atm pressure occupies 22.4 L volume.
So, 100 g CaCO
3
forms 22.4 L of CO
2
Hence, 2.5 g CaCO
3
will form =
100
2.5×22.4
=
100
56
L of CO
2
=0.56 L of CO
2
Answered by
3
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