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We know that the lens maker's Equation for thin lenses is given as:
1/f = (n-1)(1/R1 - 1/R2).
Where,
R1 and R2 = Radii of curvature of Two Sides of the lens.
n = refractive index of the material.
f = focal length.
Now,
Given R1 = 30cm.
R2 = 60cm.
n = 1.5.
Therefore,
The focal length of double convex lens 1/f = (1.5 - 1)(1/-30 - 1/60)
= (0.5)(-1/20)
= -0.025
f = -40cm.
Therefore the focal length = -40cm.
Note: I have written -30 because for a concave lens, R1 = negative and R2 = positive.
Hope this helps!
1/f = (n-1)(1/R1 - 1/R2).
Where,
R1 and R2 = Radii of curvature of Two Sides of the lens.
n = refractive index of the material.
f = focal length.
Now,
Given R1 = 30cm.
R2 = 60cm.
n = 1.5.
Therefore,
The focal length of double convex lens 1/f = (1.5 - 1)(1/-30 - 1/60)
= (0.5)(-1/20)
= -0.025
f = -40cm.
Therefore the focal length = -40cm.
Note: I have written -30 because for a concave lens, R1 = negative and R2 = positive.
Hope this helps!
saisree5:
thank u soooooooo much for answering the whole procress
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