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Proved BC = 2MN
Step-by-step explanation:
The vertices of an triangle abc area A(-3,2) B(-1,-4)and C(-5,2).if M and N are the midpoint of AB and AC respectively,show that 2MN is equal to BC
A(-3,2) B(-1,-4)C(-5,2)
M mid point of AB
M = ( -3 + (-1))/2 , (2 + (-4))/2 = ( -2 , -1)
N mid point of AC
N = ( -3 + (-5))/2 , (2 + 2)/2 = ( -4 , 2)
MN = √( (-2 -(-4))² + (-1 -2)²) = √ (4 + 9) =√13
BC= √( (-5 -(-1))² + (2 -(-4))²) = √(16 + 36) = √52 = 2√13
BC = 2MN
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