Math, asked by vishnu22332m, 1 year ago

Please answer it .It is urgent

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Answers

Answered by Anonymous

1

Answer:

To prove:

cosA•cos2A•cos4A•cos8A

= sin16A/16sinA

Note:

2sinXcosX = sin2X

Proof:

LHS

= cosA•cos2A•cos4A•cos8A

= (2sinA/2sinA)cosAcos2Acos4Acos8A

= 2sinAcosAcos2Acos4Acos8A/2sinA

= sin2Acos2Acos4Acos8A/2sinA

= 2sin2Acos2Acos4Acos8A/4sinA

= sin4Acos4Acos8A/4sinA

= 2sin4Acos4Acos8A/8sinA

= sin8Acos8A/8sinA

= 2sin8Acos8A/16sinA

= sin16A/16sinA

= RHS

Hence proved

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