Question

Please answer it on a paper and send the attachments.

Answer 1

As we see here OP is common in both triangles.

Given:

• Right-angled in ∠A, ∠B → R: Right angles
• Hypotenuse OP is common → H: Hypotenuses
• AP and BP are equal → S: Sides

Therefore, it is RHS by triangle symmetry. It is proven that two angles ∠AOP and ∠BOP are equal.

Therefore OP bisects ∠AOB.

Answer 2

Answer:

right angle A , O, B

Step-by-step explanation:

I hope this is helpful for you