please answer my question
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Hey MATE!
We are given that :
Initial velocity (u) = 90 km/hr =>
90*5/18 => 25m/sec
Final velocity (v) = 0 km/hr => 0m/s
Acceleration (a) = 0.5 m/s²
We acn apply third equation of motion here ie,
v² = u² + 2as
0² = 25² + 2(-0.5)(s)
0-25² = -s
- 625 = -s
Thus, distance travelled = s = 625 m Answer.
Hope it helps
Hakuna Matata :))
We are given that :
Initial velocity (u) = 90 km/hr =>
90*5/18 => 25m/sec
Final velocity (v) = 0 km/hr => 0m/s
Acceleration (a) = 0.5 m/s²
We acn apply third equation of motion here ie,
v² = u² + 2as
0² = 25² + 2(-0.5)(s)
0-25² = -s
- 625 = -s
Thus, distance travelled = s = 625 m Answer.
Hope it helps
Hakuna Matata :))
Answered by
1
v^2-u^2=2as
0^2-25^2=2(-0.5)s
0-625=-s
therefore, distance travelled=625m
0^2-25^2=2(-0.5)s
0-625=-s
therefore, distance travelled=625m
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