Question

please answer my question........ Quick it's a class 9th standard question...

Answer 1

see your answer in picture

Answer 2

(1). Given Equation is (3/x - 2/x^2)^3.

It is in the form of (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3.

Here a = 3/x, b = 2/x^2.

(3/x)^3 - 3(3/x)^2 * (2/x^2) + 3(3/x) * (2/x^2)^2 - (2/x^2)^3

3^3/x^3 - 3(3^2/x^2) * 2/x^2 + 9/x * 4/x^(2 * 2) - 2^3/x^(3 * 2)

27/x^3 - 54/x^2 + 36/x^5 - 8/x^6.



(2) (x/4 + 4/x)^3.

It is in the form of (a+b)^3 = a^3 + 3a^2b+3ab^2+b^3.

Here a = x/4, b = 4/x.

(x/4)^3 + 3(x/4)^2(4/x) + 3(x/4)(4/x)^2 + (4/x)^3

x^4/4^3 + 3(x^2/4^2) * (4/x) + 3(x/4)(4^2/x^2) + (4^3/x^3)

x^4/64 + 3x/4 + 12/x + 64/x^3.



Hope this helps!